Project Euler Problem 6 - Solved

Q) The sum of the squares of the first ten natural numbers is,

1² + 2² + ... + 10² = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)² = 55² = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025  385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

Solution: Python: ================= def SumSqr(n): x = (n*(n+1)/2)**2 - (n*(n+1))*((2*n+1)/6.0) return x print int(SumSqr(100))